Question

y=-2x^2+5x-1 x=0 y=0

Answer 1

What do you need to do? Find the y-intercept and then the x-intercepts ?

Answer 2

y intercept

Answer 3

to find the y-intercept, set x=0 and solve for y.

the first 2 terms 2x^2 and 5x if you make x=0 are going to turn into zero, so what's left ?

Answer 4

-1

Answer 5

Yes, there we go !

Answer 6

how do we solve for x

Answer 7

How would you solve for x-intercepts ? set y=0 and solve for x.
Like this
\[y=-2x^2+5x-1 \]\[-2x^2+5x-1 =0\]
multiply everything times -1 to make it look easier :)\[2x^2-5x+1 =0\]

(you can't factor since the discriminant isn't a perfect square, but, you can use the quadratic formula)

You want to do the quadratic formula, or should I start you off first ?

Answer 8

could you start it off not sure how to