y=x^3+x+1 solve for y y=0
the y or x intercept(s) ?
y
why do you have y=0 on the side there?
thats what i have on my worksheet
@awachter : Please start over. Include the instructions that came with this problem. What you have already posted is too ambiguous.
"solve for y y=0" this is what it says? if this is true, then you have already solved for y when y=0 maybe you mean to solve for x when y=0?
here are some graphing problems use the table of value approach include an x=0(find y) y=0(find x) and 3 other pairs. y=x^3+x+1
That's SO much clearer than before. Thanks. You are to set up a table of x and y values. Your table must show the y value when x = 0 and the x-value when y = 0, and you are to pick 3 other x-values (arbitrarily) and find y for each of them. To get you started:|dw:1399247342719:dw|
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