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Solve correct to four decimal places: 3^x =4^(x-7) What do I do since the bases are not the same?
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Take the log of both sides.
a raft of algebra
start with \[\ln(3)x=(x-7)\ln(4)\] and then solve for \(x\)
don't be confused, \(\ln(3)\) and \(\ln(4)\) are just some constants (numbers)
you got the algebra?
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Would I divide log(3) from both sides?
I canceled the logs on both sides and ended up with 3x= 4x-14 x=14
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