Find an equation for the nth term of the sequence.
-4, -16, -64, -256, ...
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OpenStudy (anonymous):
an = a1 + (n – 1)d
OpenStudy (usukidoll):
I think we need to just find an equation that produces that string
OpenStudy (usukidoll):
-(4)^n and let n = 1,2,3,4...
OpenStudy (zzr0ck3r):
-(4)^1 = -4
-(4)^2 = -16
-(4)^3 = ?
OpenStudy (usukidoll):
lol ^ that's what I'm thinking too
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OpenStudy (anonymous):
-64
OpenStudy (usukidoll):
think of it as this... ok there are - signs everywhere so we really need -... next I see a 4 16 64... hmmm square root of 16 is 4... 4^ 2 = 16.. cube root of 64 is 4... 4^3 = 64
OpenStudy (anonymous):
an = 4 • -4n
an = 4 • -4n + 1
an = -4 • 4n
an = -4 • 4n - 1
OpenStudy (usukidoll):
so your equation would be -(4)^n
OpenStudy (usukidoll):
we don't need a_n
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OpenStudy (usukidoll):
-(4)^n is the answer.. what if we let n = 1 2 3 4? then we have -4,-16,-64,-256 which is what you want right?
OpenStudy (anonymous):
yes
OpenStudy (usukidoll):
^^ then that's the answer -(4)^n is your equation
OpenStudy (anonymous):
= -4 • 4n?
OpenStudy (usukidoll):
no ^
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OpenStudy (anonymous):
4 • -4n
OpenStudy (usukidoll):
ignore JoyLin's suggestion... that's wrong
OpenStudy (anonymous):
because -4n is not one of my answer choices
OpenStudy (anonymous):
an = 4 • -4n
an = 4 • -4n + 1
an = -4 • 4n
an = -4 • 4n - 1
OpenStudy (anonymous):
thats my choices
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OpenStudy (usukidoll):
oh strange ... because you could just use what zzrocker and I said and that would be fine