Algebra 2 Help! What are the sine, cosine, and tangent of 5pi/3 radians? sin Θ = -sqrt 3/2; cos Θ = 1/2; tan Θ = -sqrt 3 sin Θ = sqrt 3/2; cos Θ = -1/2; tan Θ = sqrt 3 sin Θ = sqrt 3/2; cos Θ = 1/2; tan Θ = sqrt 3 sin Θ = -sqrt 3/2; cos Θ = -1/2; tan Θ = -sqrt 3
Use the fact that 5pi/3=2pi-pi/3
okay
@ganeshie8
Did u try it?
it made no sense to me. I thought you left which is why I asked Ganeshie8
heard of `reference angle` before ?
It makes sense. Note that we know the values of only basic angles ie 0,30,45,60,90 The given value in qn is 5pi/3 so we write it as 5pi/3=2pi-pi/3
Yes, but I don't understand it
Now sin(2pi-theta)=-sin theta cos(2pi-theta)=cos theta tan(2pi-theta)=-tan theta
This helps a lot. For example now sin 5pi/3=sin 2pi-pi/3=-sin pi/3 And we know the value of sin pi/3 as sqrt 3/2; Put a minus sign which gives you: -sqrt 3/2; Do the same process for cos and tan.
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