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Mathematics 9 Online
OpenStudy (anonymous):

Algebra 2 Help! What are the sine, cosine, and tangent of 5pi/3 radians? sin Θ = -sqrt 3/2; cos Θ = 1/2; tan Θ = -sqrt 3 sin Θ = sqrt 3/2; cos Θ = -1/2; tan Θ = sqrt 3 sin Θ = sqrt 3/2; cos Θ = 1/2; tan Θ = sqrt 3 sin Θ = -sqrt 3/2; cos Θ = -1/2; tan Θ = -sqrt 3

OpenStudy (aravindg):

Use the fact that 5pi/3=2pi-pi/3

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

@ganeshie8

OpenStudy (aravindg):

Did u try it?

OpenStudy (anonymous):

it made no sense to me. I thought you left which is why I asked Ganeshie8

ganeshie8 (ganeshie8):

heard of `reference angle` before ?

OpenStudy (aravindg):

It makes sense. Note that we know the values of only basic angles ie 0,30,45,60,90 The given value in qn is 5pi/3 so we write it as 5pi/3=2pi-pi/3

OpenStudy (anonymous):

Yes, but I don't understand it

OpenStudy (aravindg):

Now sin(2pi-theta)=-sin theta cos(2pi-theta)=cos theta tan(2pi-theta)=-tan theta

OpenStudy (aravindg):

This helps a lot. For example now sin 5pi/3=sin 2pi-pi/3=-sin pi/3 And we know the value of sin pi/3 as sqrt 3/2; Put a minus sign which gives you: -sqrt 3/2; Do the same process for cos and tan.

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