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Calculus1 14 Online
OpenStudy (anonymous):

Maximize the Yield (see attachment)

OpenStudy (anonymous):

OpenStudy (anonymous):

so i should probably take the limit?

ganeshie8 (ganeshie8):

find the derivative, set it equal to 0 and find ur critical points ?

ganeshie8 (ganeshie8):

i presume u knw optimization as i saw u doing integrals in ur past posts

OpenStudy (anonymous):

Im still working the numbers, I'm missing something for sure..

ganeshie8 (ganeshie8):

did u find the derivative ?

ganeshie8 (ganeshie8):

\(Y(N) = \dfrac{N}{1+N^2}\) \(Y'(N) = ?\)

OpenStudy (anonymous):

yeah i got (N)(-1)(1+N)^(-2) + (1+N)^-1

ganeshie8 (ganeshie8):

one sec leme check

OpenStudy (anonymous):

uhg i know what i did, i took y'(n) or (1+N)^-1 instead of -2 power

OpenStudy (anonymous):

of*

ganeshie8 (ganeshie8):

hahah try again

ganeshie8 (ganeshie8):

use quotient/product rule whichever you're friendly wid

OpenStudy (anonymous):

so i got N = 1

OpenStudy (anonymous):

after setting my new derivative to zero

ganeshie8 (ganeshie8):

Excellent !

ganeshie8 (ganeshie8):

so, N = 1 is your only critical value

OpenStudy (anonymous):

so the slope of my graph is zero at x = 1 therefore that is a min or a max

OpenStudy (anonymous):

so i need to find if it is increasing or decreasing on either side right?

ganeshie8 (ganeshie8):

Yep ! you got it !! it better give a max value as the graph is decreasing (intuitively) use second derivative to figure out whether its min/max/neither

ganeshie8 (ganeshie8):

find second derivative, evaluate it at 1

ganeshie8 (ganeshie8):

f''(1) is negative => its a max

OpenStudy (anonymous):

it is so Nitrogen level 1 maximizes the yield

OpenStudy (anonymous):

thank you :)

ganeshie8 (ganeshie8):

Correct ! graph it and see for double confirmation :)

OpenStudy (anonymous):

yeah ill graph it now, i was trying to do it without, and we did :D

OpenStudy (anonymous):

WFA sometimes prevents me from learning

ganeshie8 (ganeshie8):

ganeshie8 (ganeshie8):

lol true, WFA's job is to check ur answers... i bet you're wise enough to cheat urself :P

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