log(2x+14)=0
its fine, thx
what second equation?
WAIT, ! that is indeed a solution, whatever makes 2x+14 into 1 is the answer, because \[\log_{anything}1=0\]
\[\log(2x+14)=0\]\[2x+14=1\]\[2x=-13\]\[x=-6.5\] b/c 2x+14 has to be equal to one, so that log(2x+14) can 0
oh ok, thx :)
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k thx @SolomonZelman for the info.
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