Question

t:P2-->P2 by x^2->x^2+1, x->x^2-1, and 1->3 how would you find T=RepB,B(t) with B=

Answer 1

You have the basis {1, x, x^2}, right?
T(1) =3
T(x) = -1 +x^2
T(x^2) = 1+x^2
so that T=\(\left[\begin{matrix}3&-1&1\\0&0&0\\0&1&1\end{matrix}\right]\)

Answer 2

got what I mean?

Answer 3

yes!

Answer 4

good

Answer 5

that would be the final answer of the matrix correct?

Answer 6

yup

Answer 7

so to find S where D=<1,1+x,1+x+x^2> would T=

Answer 8

T= 1 1 1
0 1 1
0 0 1

Answer 9

yup

Answer 10

from there how do you fin matrix p=P^-1SP

Answer 11

?