Question

12x−2=20


log 12x−2=log 20


(x−2)log 12=log 20


(x−2)=log 20/log 12


x=2+log 20/log 12


x=2+log12 20

Someone finish this, need answer rounded to the nearest ten-thousandth, Thanks

Answer 1

\(\LARGE\color{blue}{ \bf 12^{x−2}=20 }\) like this ?

Answer 2

yes

Answer 3

x= ?

Answer 4

I gave you the calculator in the previous question.

Answer 5

dont know how to use it..

Answer 6

\[x-2 = \frac{ \log(20) }{ \log(12) }\]

Answer 7

can you just find what x=?

appreciate it..

Answer 8

\[x = 2+\frac{ \log(20) }{ \log(12) }\]

Answer 9

http://www.1728.org/logrithm.htm

\(\LARGE\color{blue}{ \bf Log_{~base~}(~log~of) }\)

example to use the calc.
\(\LARGE\color{blue}{ \bf Log_{2}(5) }\)

see where it says "logarithm of" ? is what you put in 5
see where it says "Number base" ? click other, and put in 2

Answer 10

When the base is NOT SPECIFIED, it is 10.

Answer 11

My nemesis logarithm calculator.

Answer 12

\(\LARGE\color{blue}{ \bf x=2+\frac{log20}{log12} }\)



\(\LARGE\color{blue}{ \bf x=2+log_{12}20 }\)


applying the rule to obtain this,

\(\LARGE\color{red}{ \bf \frac{logA}{logB} =Log_{B}A}\)

Answer 13

i guess you dont understand

Answer 14

who , me ?!?!