Question

I have a question

Answer 1

each of two urns contains green balls and red balls. urn I contains 8 green balls and 12 red balls. Urn II contains 5 green balls and 8 red balls. if a ball is drawn from each urn, what is P(red and red)?

A. 79/65
B. 24/65
C. 20/33
D. 2/13

Answer 2

Since the trials are independent of each other, meaning whatever you get out of the first urn doesn't change what you can get out of the second urn, there is a nifty formula that we have,\[P(AandB)=P(A)*P(B)\]and for your problem, you have that P(A) is the probability of getting a red ball out of the first urn, and the P(B) is the probability that you get a red in the second urn.

Answer 3

so is it B?

Answer 4

Indeed it is, great job!

Answer 5

thank you