Question

MEDAL TO ANYONE WHO GETS THIS RIGHT!! Simplify. Be sure to state the restrictions on the variables. u^2-9/(u-3)^2

Answer 1

Any ideas?

Answer 2

A.u+2/u-6
b. u+3/u-3
c. 1/u-3
d. 1/2u+12

Answer 3

$$\Huge \frac{u^2-9}{(u-3)^2}$$

Answer 4

thats not one of the answers though

Answer 5

That is the question :)

Answer 6

oh i didn't even realize that dang it sorry i'm in a hurry

Answer 7

Are you writing a test?

Answer 8

no i'm studying but the book won't give me an answer.

Answer 9

What do you know about "restrictions"?

Answer 10

i don't know ok i just need help

Answer 11

What are you not allowed to do in arithmetic?

Answer 12

IDK

Answer 13

What is 0 times any number?

Answer 14

0

Answer 15

Yes, this means you are not allowed to divide by 0. This is called a restriction. Does that make sense?

Answer 16

yes

Answer 17

it's fine i came up with an answer i don't need anymore help on this question

Answer 18

Don't forget the restrictions the question asks for.

Answer 19

ok