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Mathematics 48 Online
OpenStudy (anonymous):

In a hospital ward, there are fifteen nurses and three doctors.....

OpenStudy (anonymous):

In a hospital ward, there are fifteen nurses and three doctors. Nine of the nurses and one of the doctors are female. If a person is randomly selected from this group, what is the probability that the person is male or a doctor? nine over eighteen two over fifteen eight over fifteen eight over eighteen

OpenStudy (anonymous):

First write down what you know

OpenStudy (anonymous):

You have males - 15 nurses -9 nurses = 6 males males- 3 doctors - 1 doctor = 2 males Assuming there are no transgenders lol

ganeshie8 (ganeshie8):

lol

OpenStudy (anonymous):

That would make it 8/18 probability? No, I don't know the 'rule'..

OpenStudy (anonymous):

Total number of people are 15 +3 =18

ganeshie8 (ganeshie8):

and count how many either "male" or "doctor"

OpenStudy (anonymous):

@ganeshie8 can u continue my internet is down

OpenStudy (anonymous):

and OS is lagging

OpenStudy (anonymous):

Does it have to be a male doctor or any in general? If any, then 9/18...?

ganeshie8 (ganeshie8):

Yep !

ganeshie8 (ganeshie8):

3 doctors + 6 male nurses makes it 9 favorables

ganeshie8 (ganeshie8):

divide it by the total ppl to get the desired probability

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