Question

done

Answer 1

the first answer I got 112 the second 104 that doesnt equal 4 and 3 for either

Answer 2

I'd substitute your x value into each and see what happens

1st choice x = 1 and its

\[4 \times(3)^{1 -1} + 4 = 8\]

so that rules out the 1st equation... as when x = -1 you want y = -4

hope it helps

Answer 3

@campbell_st the part I dont get though is how do I solve w/ the exponents do I subtract the 1-1 or

Answer 4

yes 1-1=0 anything to the 0 power=1