Question

3 square root -8x

Answer 1

sorry how do you get that @Light&Happiness

Answer 2

do you mean \(\sqrt[3]{-8x}\) or \(\sqrt[3]{-8} \cdot x\)?

Answer 3

first one right?

Answer 4

first one

Answer 5

well then Light isn't really correct, it should be \(-2\sqrt[3]{x}\)

because \(\sqrt[3]{-8x} = \sqrt[3]{(-2)^3} \cdot \sqrt[3]{x} = \boxed{-2\sqrt[3]{x}}\)

Answer 6

\(-2\cdot-2\cdot-2 = -8\)