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Trigonometry 11 Online
OpenStudy (anonymous):

Find the center of the ellipse 7x^2+3y^2+6y-4=0.

OpenStudy (anonymous):

try completing the square for each variable. What do you get?

OpenStudy (anonymous):

I did that and I got.( 7x^2 +0+0) + 3(y^2+2y+1)=4+3

OpenStudy (anonymous):

do the same for x too, you haven't complete the square for x yet

OpenStudy (anonymous):

Can I pull a 7 or 0 out?

OpenStudy (anonymous):

wait... nvm, you got it right. Idk what I said in the last post

OpenStudy (anonymous):

so now, change them so that they become (x+a)^2 and (y+b)^2

OpenStudy (anonymous):

the a and b should tell you the center

OpenStudy (anonymous):

Okay! I know the y one turns into (y+1)^2 so my y coordinate is 1. What would the x won be? The zero is throwing me off?

OpenStudy (anonymous):

exactly... it's zero

OpenStudy (anonymous):

don't overthink it, haha

OpenStudy (anonymous):

Okay. Perfect! Thank you so much!

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