Ask your own question, for FREE!
Physics 17 Online
OpenStudy (somy):

Graphs!! please explain how am i supposed to draw them??

OpenStudy (somy):

question 6 has two parts about drawing on the graph so please take a look at them @Mashy

random231 (random231):

Did you find the time of constant acceleration and deceleration?

random231 (random231):

@somy?

OpenStudy (somy):

yes

OpenStudy (somy):

weight = m × g = 130.5 × 9.81 = 1280 N

OpenStudy (somy):

tension b i) F = ma T – 1280 = 130.5 × 0.57 T = 1280 + 74.4 = 1350 N

OpenStudy (somy):

tension b ii) 1280 N coz constant velocity means no acceleration so only gravity acts on the body thats why its weight

OpenStudy (somy):

Deceleration 1240 – 1280 = 130.5 × a a = (–) 0.31ms-2

OpenStudy (somy):

d i) 3.5 s d ii) 6.5 s

OpenStudy (somy):

ok this is the whole info so please now how do i draw the graph?

random231 (random231):

great! now draw a table of the time and the corresponding velocities.

OpenStudy (anonymous):

first twenty seconds a straight line? first 3.5 seconds, its accelerating with 0.57 m/s^2 .. so velocity is increasing gradually from 0 to 2m/s from t = 0 to t = 3.5 seconds. can u draw this first part?

OpenStudy (somy):

oughhh ok lets see @Mashy

random231 (random231):

|dw:1399812514160:dw|

random231 (random231):

plot the points!

OpenStudy (anonymous):

@random231 has done it all .. Random.. u pass the Cambridge course.. congrats xD

OpenStudy (somy):

owwwwwwwwww im so stupid thank u!!!!!!!!!!!!!!!!!!!!!! @random231

OpenStudy (anonymous):

@random231 last deceleration is for 6.5 seconds ya?! (thats what somy calculated :P.. i didn't calculate) if that is so, then 23.5 + 6.5 = 30s ya?!

random231 (random231):

OOH Sorry didnt notice the .5 yeah mashy you are right and @Somy pls correct it!!

random231 (random231):

|dw:1399813082261:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!