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Mathematics 15 Online
OpenStudy (anonymous):

What is the standard form of the equation of the circle in the graph

OpenStudy (anonymous):

Picture

OpenStudy (zzr0ck3r):

\((x-a)^2+(y-b)^2=r^2\) this is the standard equation of a circle at center \((a,b)\) so what is the answer?

OpenStudy (anonymous):

but in my answer choices theres no subtracting

OpenStudy (anonymous):

these are my answer choices : A.) (x + 3)2 + (y + 3)2 =3 B.) x2 + y2 = 3 C.) (x + 3)2 + (y + 3)2 =9 D.) x2 + y2 = 9

OpenStudy (zzr0ck3r):

what is the center of the circle in the picture?

OpenStudy (anonymous):

0

OpenStudy (zzr0ck3r):

what happens when you subtract 0?

OpenStudy (anonymous):

add

OpenStudy (zzr0ck3r):

so the radius is 3, and the center is \((0,0)\) so using that equation I gave \((x-0)^2+(y-0)^2=3^2 \large\rightarrow x^2+y^2=9\)

OpenStudy (anonymous):

so the answer is C

OpenStudy (zzr0ck3r):

are you just typing random things?

OpenStudy (anonymous):

no im asking you

OpenStudy (zzr0ck3r):

I say "what happens when you subtract 0" your response was "add" I say the answer is "x^2+y^2=9", your response "is the answer (x + 3)2 + (y + 3)2 =9"

OpenStudy (zzr0ck3r):

you see how im conflicted :P

OpenStudy (zzr0ck3r):

sorry just messing with you, its D)

OpenStudy (zzr0ck3r):

I hope you see why

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