What is the standard form of the equation of the circle in the graph
Picture
\((x-a)^2+(y-b)^2=r^2\) this is the standard equation of a circle at center \((a,b)\) so what is the answer?
but in my answer choices theres no subtracting
these are my answer choices : A.) (x + 3)2 + (y + 3)2 =3 B.) x2 + y2 = 3 C.) (x + 3)2 + (y + 3)2 =9 D.) x2 + y2 = 9
what is the center of the circle in the picture?
0
what happens when you subtract 0?
add
so the radius is 3, and the center is \((0,0)\) so using that equation I gave \((x-0)^2+(y-0)^2=3^2 \large\rightarrow x^2+y^2=9\)
so the answer is C
are you just typing random things?
no im asking you
I say "what happens when you subtract 0" your response was "add" I say the answer is "x^2+y^2=9", your response "is the answer (x + 3)2 + (y + 3)2 =9"
you see how im conflicted :P
sorry just messing with you, its D)
I hope you see why
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