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OpenStudy (anonymous):
What is the standard form of the equation of the circle in the graph
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OpenStudy (anonymous):
Picture
OpenStudy (zzr0ck3r):
\((x-a)^2+(y-b)^2=r^2\) this is the standard equation of a circle at center \((a,b)\)
so what is the answer?
OpenStudy (anonymous):
but in my answer choices theres no subtracting
OpenStudy (anonymous):
these are my answer choices :
A.) (x + 3)2 + (y + 3)2 =3
B.) x2 + y2 = 3
C.) (x + 3)2 + (y + 3)2 =9
D.) x2 + y2 = 9
OpenStudy (zzr0ck3r):
what is the center of the circle in the picture?
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OpenStudy (anonymous):
0
OpenStudy (zzr0ck3r):
what happens when you subtract 0?
OpenStudy (anonymous):
add
OpenStudy (zzr0ck3r):
so the radius is 3, and the center is \((0,0)\)
so using that equation I gave
\((x-0)^2+(y-0)^2=3^2 \large\rightarrow x^2+y^2=9\)
OpenStudy (anonymous):
so the answer is C
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OpenStudy (zzr0ck3r):
are you just typing random things?
OpenStudy (anonymous):
no im asking you
OpenStudy (zzr0ck3r):
I say "what happens when you subtract 0" your response was "add"
I say the answer is "x^2+y^2=9", your response "is the answer (x + 3)2 + (y + 3)2 =9"
OpenStudy (zzr0ck3r):
you see how im conflicted :P
OpenStudy (zzr0ck3r):
sorry just messing with you, its D)
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OpenStudy (zzr0ck3r):
I hope you see why
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