Question

:) Who wants an easy medal???

Express 5^3 = x as a logarithmic equation.

log(5)3 = x

log(3)5 = x

log(3)x = 5

log(5)x = 3

I just totally blanked.

Answer 1

You pull the exponent out front in the log rule

Answer 2

\[\large b^x=y\iff \log_b(y)=x\]

Answer 3

yes, what @satellite73 said

Answer 4

Soo.... log(3)5=x ????

Answer 5

\[5^3=125\iff \log_5(125)=3\] in other words

Answer 6

I'm confused...So it's log(5)x=3

Answer 7

did you understand anything about the log rules?

Answer 8

its been a while, i kinda forgot

Answer 9

if you have 3^2 = 9 so it is log3(9) = 2

Answer 10

log(b)y=x
right?

Answer 11

the number on the outside is the base and then the value with your exponent at the end

Answer 12

5^3=x, 5 is the base so you have log5(x)=3

Answer 13

hope that helps out

Answer 14

yea thank you :)