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:) Who wants an easy medal??? Express 5^3 = x as a logarithmic equation. log(5)3 = x log(3)5 = x log(3)x = 5 log(5)x = 3 I just totally blanked.
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You pull the exponent out front in the log rule
\[\large b^x=y\iff \log_b(y)=x\]
yes, what @satellite73 said
Soo.... log(3)5=x ????
\[5^3=125\iff \log_5(125)=3\] in other words
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I'm confused...So it's log(5)x=3
did you understand anything about the log rules?
its been a while, i kinda forgot
if you have 3^2 = 9 so it is log3(9) = 2
log(b)y=x right?
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the number on the outside is the base and then the value with your exponent at the end
5^3=x, 5 is the base so you have log5(x)=3
hope that helps out
yea thank you :)
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