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Algebra 20 Online
OpenStudy (anonymous):

Simplify.

OpenStudy (anonymous):

x / 7x + x^2

OpenStudy (anonymous):

OpenStudy (anonymous):

I know its either A or C, I just need help finding the other part.

jimthompson5910 (jim_thompson5910):

What do you get when you factor 7x + x^2

OpenStudy (anonymous):

x(7 + x) ?

jimthompson5910 (jim_thompson5910):

good, then the x terms cancel

jimthompson5910 (jim_thompson5910):

\[\Large \frac{x}{7x+x^2}\] \[\Large \frac{x}{x(7+x)}\] \[\Large \frac{\cancel{x}}{\cancel{x}(7+x)}\] \[\Large \frac{1}{7+x}\]

jimthompson5910 (jim_thompson5910):

To make sure the first and last expressions are 100% equivalent, we need to make sure that x is not 0 and x is not -7 we do this to avoid division by zero errors in the first expression

jimthompson5910 (jim_thompson5910):

you find x = 0 and x = 7 by setting the denominator equal to zero and solving x(7+x) = 0 x = 0 or 7+x = 0 and I'm sure you see how to finish up

OpenStudy (anonymous):

So it would be C?

jimthompson5910 (jim_thompson5910):

correct

OpenStudy (anonymous):

Thank you very much!

jimthompson5910 (jim_thompson5910):

if we left out x =/= 0, then x = 0 would work in the last expression BUT it wouldn't work in the first one so this would throw off the fact the first and last expressions were 100% equal

jimthompson5910 (jim_thompson5910):

but excluding 0 fixes that

jimthompson5910 (jim_thompson5910):

you're welcome

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