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Mathematics 9 Online
OpenStudy (anonymous):

IS THIS A PERMUTATION OR COMBINATION?!! PLEASE HELP!!

OpenStudy (anonymous):

how many 6 member hockey teams can be made form 12 players. if the goalie must be the same player every time

OpenStudy (anonymous):

i tried to set it up as 11C5 + 1 but is that right? i'm not even sure if it's a combination

OpenStudy (kropot72):

If the goalie must be the same player in each combination, then we are left with 11 players choose 5.

OpenStudy (anonymous):

so i was correct?

OpenStudy (anonymous):

u have (12 ways to choose the same goalie) "AND" choose ( 5 others among 11)

OpenStudy (anonymous):

should i use a permutation because i don't think repetition can count in this case?

OpenStudy (anonymous):

someone please help me

ganeshie8 (ganeshie8):

\(^{11}C_5\) is right

ganeshie8 (ganeshie8):

its clearly a combination cuz the order in which u select the players dont affect the team : team {a, b, c} is same as team {b, a, c}

OpenStudy (anonymous):

so should i set this up as C(11,5) + 1 in order to account for the goalie?

ganeshie8 (ganeshie8):

good question :) goalie is already selected, so u can forget about choosing goalie again

ganeshie8 (ganeshie8):

since the goalie is already selected, your job is only to select 5 other players from the remaining 11 players

ganeshie8 (ganeshie8):

C(11, 5) is the final answer

OpenStudy (anonymous):

thank you so much!

ganeshie8 (ganeshie8):

you're welcome !

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