Question

Help please.

Answer 1

@Reaper534

Answer 2

@hartnn

Answer 3

Ohh gosh honestly idk @hartnn can u help i would like to learn this too

Answer 4

alright :s

Answer 5

in the meantime can you help me with this one ? ;O

Answer 6

does this question belong to calculus ?
how do you usually find minimum value ?

Answer 7

i have no idea :/

Answer 8

assuming its not calculus, lets first try to find the vertex of that quadratic function ,
\(\Large f(x)= 2 (x^2+14x-4)\)

have you learnt the method of completing the squares before ?

Answer 9

ok, and no :/

Answer 10

then lets use the direct formula here,
for a>0 and
\(\Large f(x) = ax^2+bx+c \)
the minimum value is just
\(\Large c -\dfrac{b^2}{4a}\)

so first find the values of a,b,c

Answer 11

compare \(ax^2+bx+c \: \: with \\ 2x^2+28x-8\)

Answer 12

could you get values of a,b,c by comparing ?