Question

Help please!

Answer 1

@alias

Answer 2

@Euler271

Answer 3

raise each side to the fifth power. That should get rid of the exponent. Then solve the usual way to find x

Answer 4

(make both sides)^5

you have

-2x + 6 = -8 + 10x

solve for x.

now realize that:\[x^{1/5} = \sqrt[5]{x}\]

extraneous solutions would be those that make either bracket = 0 since you can't have a negative root in "real numbers"

Answer 5

wow i just read what i wrote..

Answer 6

the last sentence in completely wrong.

it should say: extraneous solutions would be those that make the bracket < 0 on either side. for the same reason.

not = 0 though. that's fine.

Answer 7

C :s @alias

Answer 8

@Euler271

Answer 9

amswer is not C...

So after you raise each side by 5
-2x + 6 = -8 + 10x

Answer 10

x should be 14/12, then simplify it to get your answer :)

Answer 11

B :)

Answer 12

thank u !

Answer 13

it's A

Answer 14

Check you math... 14/12 when simplified has to be larger than 1, and B is less than 1 so it's not right.

Always check your answer and use common sense :P