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The life expectanct of a typical lightbulb is normally distributed with a mean of 4,000 hours and a standard deviation of 42 hours. What is the probability that a lightbulb will last between 3,875 and 4,055 hours?
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use normal distribution to find z
do it involve conditoinal probability
nope
hmm lemme see
There actually is a special formula for exactly this type of tasks. \[P(\alpha < x < \beta) = \Phi(\frac{\beta - a}{\sigma}) - \Phi(\frac{\alpha- a}{\sigma})\] where alpha and beta are your bounds. a is mathematical expectation and sigma is square root of variance.
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sigma is standart deviation. a is your mean. Phi is a function usualle taken from the table.
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