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Mathematics 9 Online
OpenStudy (anonymous):

The life expectanct of a typical lightbulb is normally distributed with a mean of 4,000 hours and a standard deviation of 42 hours. What is the probability that a lightbulb will last between 3,875 and 4,055 hours?

OpenStudy (anonymous):

use normal distribution to find z

OpenStudy (usman1995):

do it involve conditoinal probability

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

hmm lemme see

OpenStudy (anonymous):

There actually is a special formula for exactly this type of tasks. \[P(\alpha < x < \beta) = \Phi(\frac{\beta - a}{\sigma}) - \Phi(\frac{\alpha- a}{\sigma})\] where alpha and beta are your bounds. a is mathematical expectation and sigma is square root of variance.

OpenStudy (anonymous):

sigma is standart deviation. a is your mean. Phi is a function usualle taken from the table.

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