Question

Please someone help me with this question.
A second transverse wave T2, of amplitude A has the same waveform as wave T1 but
lags behind T1 by a phase angle of 60°. The two waves T1 and T2 pass through the
same point.
(i) On Fig. 5.1, draw the variation with time t of the displacement x of the point in
wave T2.

Answer 1

\[\phi = \frac{2\pi}{\lambda} x\]

phi = phase difference
x equals distance between the waves

Answer 2

Equation of the transverse wave is y= Asin(wt+phi)
here, A is the amplitude, w is the angular frequency, t is the time and phi is the phase difference.

since T1 is y=Asin(wt) therefore for T2 y= Asin(wt-60).

now follow the formula by thushananth to find the path difference where,

Answer 3

i think u can directly find x which is the distance between the two waves

i found that x = 0.5 cm so