What is the graph of the function?
\[f(x)=\frac{ 1 }{ 3 }x ^{2}\]
plug in x values and tell me what you get for f(x) when x=-2,-1,0,1,2 write 5 ( x, f(x) ) coordinates.
blocking someone prevents just from messaging, not from replying to your questions; unfortunately.
That's stupid then what's the point lol and okay
The point is that the user won't message you, but if he/she curses you in a question, then a moderator sees all deleted and edited replies so...
anyway ...
Yes, tell me what f(x) equals, when x=2, f(x)=? x=-1, f(x)=? x=0, f(x)=? x=1, f(x)=? x=2, f(x)=?
f(x) = -1.3 repeating f(x) = -0.3 repeating f(x) = 0 f(x) = 0.3 repeating f(x) = 1.3 repeating
for the first 2 , it is positive becuase \[(-2)^2=4,~~~~no t~~-4\]
ok ..
what would the graph look like
you can see that \[x=0~~,~~~~f(x)=0\]\[x=±1~~,~~~~f(x)=~1/3\]\[x=±2~~,~~~~f(x)=~4/3=1,~1/3\]\[x=±3~~,~~~~f(x)=~9/3=3\]
@ranga
I'm still confused on what the graph would look like though
Graph the points on your paper and tell me what it looks like.
Or graph the points anywhere else. You can see that it is a U shaped parabola
Would this be the right graph ?
It is stepper, it contains points (3,9) and (-3,9) (and not (3,3) and (-3,3) )
So that's wrong ?
I have no idea what i'm doing am I not understanding what you're trying to say
Yes, this graph is wrong. It is close to truth, because it is centered at the origin and goes up, but it is steeper, . Steeper !
Oh, my bad... 1/3, yeah it is correct. I am really sorry -:(
Yes it's right. I don't want to confuse you anymore. Have a good one.
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