Question

Can someone check my answer/solutions please

Answer 1

@douglaswinslowcooper

Answer 2

Your solution to part A looks fine to me (I didn't check the actual numbers, but the approach looks good).

Answer 3

Yes. Approach to A seems correct.

B. Time in region E: we know the velocity but not the length of region E, so we have to solve this from the deflection distance. use 1 cm = (1/2) (F/m) t^2,
with F = qE and m the mass of the electron. this gives you the time in the E field.
a = F/m.
get F = qE from a = F/m

C. Outside the field, no curvature (negligible gravity), just the vector sum of the final vertical and horizontal velocities calculated above (from A and from
B. v=at)