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Mathematics 24 Online
OpenStudy (henrietepurina):

Re Opened Question...

OpenStudy (henrietepurina):

OpenStudy (henrietepurina):

Answer choices

OpenStudy (henrietepurina):

it says evaluate...

hero (hero):

So first you need to change everything to fractions. \(\sqrt[5]{8} = 8^{1/5}\) \(\sqrt{8} = 8^{1/2}\) \(\sqrt[3]{8^5} = 8^{5/3}\)

hero (hero):

Which means what you have to begin with in fraction form is \[\frac{8^{1/5}8^{1/2}}{8^{5/3}}\] Which is equal to \[\frac{8^{1/5 + 1/2}}{8^{5/3}}\]

OpenStudy (henrietepurina):

8 and 2/10 divided by 9 and 2/3?

hero (hero):

1/5 + 1/2 = 2/10 + 5/10 = 7/10 So \[\frac{8^{7/10}}{8^{5/3}}\]

hero (hero):

And now.... \[8^{7/10-5/3}\]

hero (hero):

7/10 - 5/3 should get you the correct result

OpenStudy (henrietepurina):

21/30 - 50/30 = -29/30

hero (hero):

Congrats

OpenStudy (henrietepurina):

OMG there is a choice like that thanks so much ive been on this for 2-3 hrs tnx

hero (hero):

It's easy when you don't make any mistakes

OpenStudy (henrietepurina):

thanks but i still got 31/50

hero (hero):

What do you mean?

hero (hero):

You got 31/50 for a grade?

OpenStudy (henrietepurina):

yeah, sad but the last one was righ but the rest werent because people lied to me on here

hero (hero):

They probably made mistakes like I did. It happens. But you should learn how to check other people's computation. Everyone makes mistakes. You should make that assumption even when others are helping and double check behind them. No one else will do it for you.

OpenStudy (henrietepurina):

Ok, thanks a gazillion times goodnight! :)

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