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simplify tan^2(x)-tan^2(x)sin^2(x)
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start by factoring out `tan^2(x)`
tan^2(x)-tan^2(x)sin^2(x) tan^2(x)[1 - sin^2(x)]
what trig identity allows one to factor out the tan^2x? , I'm having trouble grasping the concept
That is not an identity. Its just the distribution property a(1-b) = a-ab for you a = tan^2(x) and b = sin^2(x)
ah okay,
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Use trig identity to simplify what ganeshie did before: 1 - sin^2(x) = ? Also write tan^2(x) as sin^2(x) / cos^2(x). Then simplify.
got it. thanks!
You are welcome.
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