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the gravitational field in a region is given by I=(3i+4j) N/kg. work done by this field is zero when a paritle is moved along a line. what is the equation of the line?
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@douglaswinslowcooper
well workdone is zero when field is normal to the displacement ok!!! now first tell me what is the slope of the line
slope would be tan(theta)
yup I=3i+4j what is tan(theta) for this equation???can u tell me
its 4/3
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so what is the slope of the line perpendicular to it??
its -(3/4) is'nt it?
yes because product of slopes of two perpendicular line is =-1 now as u know y=mx so \[y=\frac{ -3 }{ 4 }x\] thats the equation of the line
oh now i get it thank u
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