Question

HELP please

Answer 1

@kx2bay

Answer 2

@geniousmind13

Answer 3

I am sorry can't help you here but you might want to try @jzellem1004 or @Xmoses1 they are really great at math!!

Answer 4

oh okay thanks :3

Answer 5

your welcome

Answer 6

Well i am at the middle of learning this, so i really am not 100% on this but i would defentantly pick D.

Answer 7

thanks! :) i'll make sure tho @helder_edwin

Answer 8

ok
ill call in to
@mathmale

Answer 9

@mathstudent55

Answer 10

...

Answer 11

ahhh

Answer 12

@emcrazy14

Answer 13

It's C. Do you want me to walk you through it?

Answer 14

yes please.

Answer 15

Okay, you'll first need to factorise y^2 + y + 6.
You'll get (y+3) (y+2)

Answer 16

So your fraction will be \[\frac{ (y-1) }{ (y+3)(y+2) } \times \frac{ (y+3) }{ (y+6) }\]

Answer 17

Sorry, that's y-6.
The (y+3) will cancel out. And so you'll be left with the expression given in C.

Answer 18

ahhh okay can you help me with one more ^_^

Answer 19

\[-4(x+5)=-1(x+1)\]
\[-4x-20=-x-1\]
\[-4x+x=-1+20\]

Answer 20

\[-3x=19\]

Answer 21

So what do you think your answer is now?

Answer 22

C :) @emcrazy14

Answer 23

Yes, correct.

Answer 24

thanks!