Question

Okay so I found the second derivative of this problem: ln(x^2-3x) at x= -1
and I got 15/16. Is this correct?

Answer 1

You mean you need to find the value of the second derivative of ln (x^2 - 3x) at x = -1?

Answer 2

yes

Answer 3

f"(x)=(-1/x^2 -1/(x-3)^2)+C

Answer 4

It's wrong

Answer 5

the second derivative?

Answer 6

The answer, your second derivative is correct, excluding the C

Answer 7

so my evaluating is wrong

Answer 8

Yes

Answer 9

-17/16

Answer 10

Yep