y ≥ -2x - 2 y + x ≥ 0 Describe the steps to graph the solution set to the system of inequalities.
@Hero
First get y by itself. so for y + x ≥ 0 subtract x from both sides and get y≥-x. Then look at the inequalities. The last number (that is without a variable) is where you start on the y-axis. Ex. y ≥ -2x - 2 graph would intercept the y-axis at -2. Then you look at the number with x variable and put into a fraction and this will be your slope. Ex. y ≥ -2x - 2 graph would have -2/1 slope (rise/run) so ypu would go down two blocks and over one and that will get you your line for your graph.
Ty so much. can you help me with one more question?
A system of equations is shown below. 3x + 8y = 12 2x + 2y = 3 Part A: Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other. Show the steps to do this. Part B: Show that the equivalent system has the same solution as the original system of equations.
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