Describe the vertical asymptote(s) and hole(s) for the graph of
@ganeshie8
hum that is a tricky question but if u really think about it it is rally nice and easy...tell u what what is ur educated guess and we will start frm there
B @Kayla_Is_Smart
yes that is correct i knew u had it in u...if i am wrong then they mustve messed up on the question cuz im 100% sure that is the answer....hope that helped
thaank you kayla :-) ill double though
@alias
ok lol
to tell if you have an asymtote or a hole, first try to simplify the equation So, you can simplify it down to (x-3)/(x-5)
so... the reason why you have an asymtote or a hole at some point is because your function is undefined at that point (if the bottom equals 0, then you can't solve it) So, the question you should ask yourself is at what x does it make the bottom equal to 0
ok... so the denominator is (x-1)*(x-5), it's obviously that either 1 or 5 would make it equal to 0 right? So your function is undefined at those points
and since you can simplify and cancel out (x-1) in the equation, you know that at x=1 it'll just just be a hole, while the other one, at x=5 it'll be an asymtote
mmm i believe its A.
yup
ty. great explaining
you're welcome :)
sorry i gave u the wrong answer...i feel so bad now :(
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