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In a game, 10 red and 10 black cards are placed in a hat. A player draws 3 cards. Find the number of combinations for drawing 1 red and 2 black?
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anybody?
Is more information given? Like are the cards all the same, 10 identical black and 10 red, or are we talking playing cards?
Either way the simplest way to solve this is just make a list of the possible combinations, there aren't going to be that many. I'll start one, and you finish it.
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There are 10 ways of drawing one red card. Each of these 10 ways can be combined with each of the number of combinations of black cards taken 2 at a time. Therefore the total number of combinations is given by: \[10C1\times10C2=450\]
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