What is the amplitude, period, and phase shift of f(x) = −3 cos(4x + π) + 6?
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OpenStudy (anonymous):
Y = Asin(Bx-C)+D
A = amplitude
2pi/B = period
C/B = phase shift
OpenStudy (anonymous):
I've tried solving and i keep getting confused
OpenStudy (anonymous):
amplitude = 3; period = pi over two; phase shift: x = negative pi over four
amplitude = −3; period = pi over two; phase shift: x = pi over four
amplitude = −3; period = negative pi over two; phase shift: x = negative pi over four
amplitude = 3; period = 2π; phase shift: x = negative pi over four
these are my options
OpenStudy (anonymous):
what did you get when you solved it?
OpenStudy (anonymous):
i think its either a or d?
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OpenStudy (anonymous):
I'm thinking a
OpenStudy (anonymous):
hello?
OpenStudy (anonymous):
Remember the amp is A the full A including the sign
OpenStudy (anonymous):
so I'm wrong?
OpenStudy (anonymous):
yeah
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OpenStudy (anonymous):
so b ?
OpenStudy (anonymous):
lets work it one by one
A = |-3| = 3
period = 2pi/4 = pi/2
phase shift = -pi/4