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OpenStudy (anonymous):
solve on 0<=x<2pi sinx-cosx=1
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OpenStudy (solomonzelman):
tired, but... sinx-cosx=1 sinx=1+cosx sin^2x=1+cos^2x +2cos(x) sin^2x=sin^2x + 2cos(x) 2cos(x)=0 cos(x)=0
OpenStudy (solomonzelman):
except that your interval is [0 , 2π)
OpenStudy (anonymous):
thanks
OpenStudy (solomonzelman):
Anytime, if that helps you.
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