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What is the equation of the line that has a slope of -3 and passes through (1,6) A.y=-3x-1 B.y=-3x+11 C.y=-3x+9 D.y=-3x+1
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You are given the slope so plug that into the formula: y-y1=-3(x-x1) to get your equation
@Juanita35
So i plug in the point i have
yes, so you plug in the point and solve for the equation
what did you get?
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So it would be y-6=-3(1-x1
almost
y - 6 = -3(x - 1)
and then you would have y - 6 = -3x + 3
Oh i see you distrubated
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you want to distribute
and get y all by itself
By moving the 6
correct, so you would add 6 to both sides
Would it be -3x+9
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nice job :)
Thank you so much !
I am glad I can help
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