Question

Help please

Answer 1

@satellite73

Answer 2

There are many things you can do to solve this but what would you normally do to solve fractions that do not have a common denominator?

Answer 3

Find the common denominator \[(a-b)(a+b)=a^2-b^2\]
\[Use:~~~1-\sin^2x=\cos^2x\]for the bottom


Add the tops,

tell me what you got.

Answer 4

2/cos^2(x)=2...?

Answer 5

Yes, exactly

\(\large\color{blue}{ \bf 2/cos^2(x) }\) it is not equal to anything though, it is a
"simplify it!" question.

Answer 6

or even simpler,

2sec^2(x)