Write a formula for f(x) = sqrt(x) reflected over the x axis and horizontally stretched by a factor of 2
I think it is g(x) = (-1/2sqrt(x))
@whpalmer4
@iambatman
to reflect something over the x-axis, multiply it by -1 to stretch something horizontally, you need to change the argument of the function. either multiply by 2, or divide by 2, you work it out...
\[f(\sqrt{-1/2x})\]
@matricked
follow what whpalmer4 has posted..
I don't understand the stretching horizontally... reflecting is -(fx)
So if you want to horizontally stretch something what does that mean? Well think of the picture. If it got stretched to twice as long then that means you have to go twice the distance you'd normally have to go to get to the same point again, right? Since we're walking on the x-axis that means that at "2x" we are really at our old "x" point right? So we need to divide by 2 and make it only look like we're walking half as much. So in a sense dividing our walking distance by a half is the same as if the world around us doubled.
OK, so was my answer correct with the 1/2?
Since it is horizontally stretched by 2, we want to divide by 2 or multiply by 2. I know that stretching means it will be greater than 1 and compressing would be less than 1.
So I think my answer is wrong
@Kainui
o you also need help @jtryon
y = f(bx), 0 < b < 1 stretch by a factor of 1/b
what I understand from this is that the value has to be less than 1
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