Please help with geometry question? Medal awarded

Question

anonymous · Answer

The figures below are similar 







what are a) the ratio of the perimeters and b) the ratio of the areas of the larger figure to the smaller figure? The figures are not drawn to scale.

anonymous · Answer

$$a. \frac{ 8 }{ 3} and \frac{ 49 }{ 4}          b. \frac{ 7 }{ 2} and \frac{ 49 }{  }$$ $$c. \frac{ 7 }{ 2 } and \frac{ 9 }{ 4}                d. \frac{ 8 }{ 3} and \frac{ 9 }{ 4}$$

anonymous · Answer

b is 6/2 and 49/4***

anonymous · Answer

@ganeshie8 @phi @jigglypuff314

phi · Answer

I think you mean 7/2  and 49/4

yes.
the sides have a ratio of 28/8
simplify.  notice you can divide top and bottom by 4 to get 7/2
(or you could notice top and bottom are even, so divide by 2 to get 14/4  and then notice you can divide top and bottom by 2 again, to get 7/2
)

phi · Answer

if two *similar* figures have sides in the ratio of a/b  then the area will be a^2/b^2

(you square the ratio to get the ratio of their areas)
here 7/2  squared is (7/2)*(7/2) = 49/4

anonymous · Answer

Okay, makes sense now. Thank you!