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Mathematics 21 Online
OpenStudy (anonymous):

Im trying to find the sine of

jimthompson5910 (jim_thompson5910):

Is there a drawing?

OpenStudy (anonymous):

the triangle has a hyp. of 37 the opposite angle is 12 and the adj. angle is 35

OpenStudy (anonymous):

also the options are .324, .547 .789 .946

jimthompson5910 (jim_thompson5910):

so we have this? |dw:1400548497939:dw|

OpenStudy (anonymous):

yes sorry, my computer made me restart

jimthompson5910 (jim_thompson5910):

that's ok

jimthompson5910 (jim_thompson5910):

what answer did you get

OpenStudy (anonymous):

putting in sin(12/37 isnt working and sin^-1 didnt either. 0.0056604(sin) 18.924(sin inverse)

jimthompson5910 (jim_thompson5910):

sin(A) = opposite/hypotenuse sin(A) = 12/37 sin(A) = 0.32432432432432 That's all you need to do for something like this

jimthompson5910 (jim_thompson5910):

|dw:1400549214509:dw|

OpenStudy (anonymous):

what im i typing in wrong then?

jimthompson5910 (jim_thompson5910):

you're not taking the sine of 12/37 you're simply just evaluating 12/37

jimthompson5910 (jim_thompson5910):

because the sine of angle A is the ratio of the opposite side over the hypotenuse

OpenStudy (anonymous):

o thank you!!

jimthompson5910 (jim_thompson5910):

you're welcome

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