Question

The probabilities of the top-selling menu item of the family restaurants in four towns being vegetarian and different types of non-vegetarian sandwiches are given in the table.
If a family restaurant in Town 2 has a non-vegetarian sandwich as its top-selling menu item, what is the probability that it is a tuna sandwich?

Answer 1

@SithsAndGiggles can u help me please?

Answer 2

You have to find the following conditional probability:
\[P\left(\text{tuna}~|~\text{non-vegetarian}\right)=\frac{P\left(\text{non-vegetarian, tuna}\right)}{P\left(\text{non-vegetarian}\right)}\]
Clearly, the numerator will be \(6.58\%=0.0658\), since that's the associated probability for Town 2.

The denominator would be the total (marginal) probability that a given top-menu-sandwich is non-vegetarian, which is the sum of all the non-vegetarian entries in the bottom row.
(\(23.99\%=0.2399\))

Keep in mind that's I'm prone to make errors once in while, so I might be wrong.

Answer 3

Thank you!!!!!