Question

how would you solve this?
tan(theta) + 3cot(theta) = 5sec(theta)

Answer 1

may be change everything into sin/cos

Answer 2

and see if u can get a quadratic/cubic in sin or cos alone

Answer 3

good luck
i checked wolfram and \(\frac{\pi}{6}\) works, but i am not sure how to get it other than checking it

Answer 4

i have gotten up to here 2*sin^2(theta) + 5*sin(theta) - 3 = 0

Answer 5

i see a quadratic in sin... dive in and give it a try

Answer 6

that looks right ^

Answer 7

oh that looks promising
but there are others that you might miss

Answer 8

use quadratic formula or factor it

Answer 9

2*sin^2(theta) + 5*sin(theta) - 3 = 0

analogous to :

2x^2 + 5x - 3 = 0

Answer 10

which, by some miracle, factors!