Simpson's Method Help!
Hello, I am doing an 'abstract' question for finding the area under polynomials using Simpson's rule with 2 intervals.

The question is y=x^2 from x=c to x=d

so therefore y0=c^2 y1=(c+d/2)^2 y2=d^2

and with=b-a/2 therefore w=d^2-c^2/2

Simpsons Rule is w/3[y0+y2+4(y1)]
therefore= d^2-c^2/2/3[c^2+d^2+4(c^2+d^2/2)^2]
= d^2-c^2/6[c^2+d^2+4(c^2+d^2/2)^2]

could someone please tell me if this is correct so far and how to simplify the equation?
many thanks!

Question

Simpson's Method Help!
Hello, I am doing an 'abstract' question for finding the area under polynomials using Simpson's rule with 2 intervals.

The question is y=x^2 from x=c to x=d

so therefore y0=c^2    y1=(c+d/2)^2    y2=d^2

and  with=b-a/2 therefore w=d^2-c^2/2

Simpsons Rule is w/3[y0+y2+4(y1)]
therefore= d^2-c^2/2/3[c^2+d^2+4(c^2+d^2/2)^2]
= d^2-c^2/6[c^2+d^2+4(c^2+d^2/2)^2]

could someone please tell me if this is correct so far and how to simplify the equation?
many thanks!

anonymous · Answer

is it  supposed to have brackets above around the width = (b-a)/2 ?

anonymous · Answer

I don't think your simplification is correct, I get this:
|dw:1400584548523:dw|