Question

If a line crosses the y-axis at (0, 1) and has a slope of 45, what is the equation of the line?

4y − 5x = 5

y − 4x = 5

5y + 4x = 5

5y − 4x = 5

Answer 1

there is 2 ways to do this.
You can either use point-slope formula (y - y1 = m(x - x1), or you can just use slope-intercept formula (y = mx + b)

Before I go any further, are you sure your slope is 45 ?

Answer 2

oh sorry, its 4/5

Answer 3

which formula do you want to use....or does it matter ?

Answer 4

y=mx=b

Answer 5

y=mx+b

Answer 6

y = mx + b
slope(m) = 4/5
(0,1)...x = 0 and y = 1
now we sub
1 = 4/5(0) + b
1 = b

y = 4/5x + 1 --- multiply everything by 5 to get rid of the fraction
5y = 4x + 5 -- subtract 4x from both sides
5y - 4x = 5 <== your equation

Answer 7

Thank you!