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Mike asks Caroyln to pick a number at random from 1 to 100, and then asks Janie to do the same. what is the probability that both girls will select the number 49.
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The first digit has two possible choices. The second has three. The third has five. The number of possible 3-digit numbers would be \(2\times3\times5=30\).
Thank You! And can I ask another question?
Mike asks Caroyln to pick a number at random from 1 to 100, and then asks Janie to do the same. what is the probability that both girls will select the number 49.
Could I get help if that's ok?
There are 100 possible choice for each girl to pick...so there are 100*100 possible combinations of choices. One of those is 49, 49
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