Question

Help Solving Exponents? ~Confused To The Max~
1. m^2n^0
2. -3f^3g^-1

Answer 1

Cool expressions

Answer 2

\(n^0=1\) so the first one is \(m^2\)

Answer 3

\[-3f^3g^{-1}=-\frac{3f^3}{g}\] not sure what else they want you to do

Answer 4

@satellite73 I think the first one is m^2n^0. If you take 2n^0 this is equivalent to 1, so you would get m^1.

Answer 5

no

Answer 6

I was writing how to do the second one and I just realized sat already did >_>

Answer 7

\[x ^{-n}=\frac{ 1 }{ x^n }\]

Answer 8

Thanks for the help ya'll.