Question

if y varies inversely as the square of x and y=50 when x=4, find y when x=5

Answer 1

y varying inversely to the square of x is saying that y = k/x^2.

Answer 2

So, plug in your first set of numbers and find k

Answer 3

ok I got that part. my answer was 160

Answer 4

50=k/(4^2)
50=k/16
k=800<--- this was the first step
now y=800/(5^2)
y=800/25
y=??

Answer 5

huh, well y would be 32
but that's not the answer I got

Answer 6

you forgot to square the 5 and just divided 800 by 5 instead of 25

Answer 7

can you find my mistake?
y(x^2) =y(x^2)
50(4^2)/5=y(5^2)/5
y=160

Answer 8

tbh, not even sure what you're trying to do with that :/

\[y =(k/x^2) --> 50 = k/16 --> k = 800\]

\[y = k/x^2 ---> y = 800/5^2 ---> y = 800/25\]

Answer 9

ok, I guess I understand

Answer 10

will you help me with 3 more