if y varies inversely as the square of x and y=50 when x=4, find y when x=5

Question

jziggy · Answer

y varying inversely to the square of x is saying that y = k/x^2.

jziggy · Answer

So, plug in your first set of numbers and find k

anonymous · Answer

ok I got that part. my answer was 160

acxbox22 · Answer

50=k/(4^2)
50=k/16
k=800<--- this was the first step
now y=800/(5^2)
y=800/25
y=??

anonymous · Answer

huh, well y would be 32
but that's not the answer I got

acxbox22 · Answer

you forgot to square the 5 and just divided 800 by 5 instead of 25

anonymous · Answer

can you find my mistake?
 y(x^2) =y(x^2)
50(4^2)/5=y(5^2)/5
y=160

jziggy · Answer

tbh, not even sure what you're trying to do with that :/

$$y =(k/x^2) --> 50 = k/16 --> k = 800$$

$$y = k/x^2 ---> y = 800/5^2 ---> y = 800/25$$

anonymous · Answer

ok, I guess I understand

anonymous · Answer

will you help me with 3 more