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Identify the equation of the parabola.
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the vertex form of a parabola is \[y=a(x-h)^2+k\] What a does If a> 0, the parabola opens upwards if a< 0, it opens downwards. If a is positive then the parabola opens upwards like a regular "U". If a is negative, then the graph opens downwards like an upside down "U". (h,k) is the vertex the vertex in the picture is (0,0), but why is there a dot at x-axis 2?
|dw:1400652734622:dw|
the dot is the focus... I think
oh, since the parabola is on the axis, the y and x of the vertex form should switch the previous vertex form of the parabola i showed was for graphs that looks like this y=a(x-h)^2+k |dw:1400652844398:dw| but your graph should look like this x=a(y-h)+k |dw:1400652891132:dw|
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