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let Q (x,y) and P (3,4) be points on the circle x^2+y^2=25. Find the slope, m, of the line joining P and Q in terms of x.
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x^2+y^2=25 do u know how to find its diff ?
i mean do u kno how to diffrentiate it ?
nope. I know how to differentiate linear equations, but not circle equations
will \(\large x^2+y^2=25\) \(\large y=\sqrt{25-x^2}\)
oh ok. So then would I rewrite the coordinates for Q as\[(x,\sqrt{25-x^2})\] and solve for the slope as y/x ?
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using point P with Q
yess
Would the slope be\[\frac{ 4-\sqrt{25-x^2} }{ 3-x }\]
but not y/x dy/dx (derivative)
ok. thank you so much for your help.
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np :)
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